. : News : . . : Message of the Week : .
You are currently viewing an archive of the Wilderness Guardians clan's IPB1 forums.

These forums were used by WG from 2008 to 2011, and now exist for historical and achival purposes only.

For the clan's current forums, CLICK HERE.
"You are a Wilderness Guardian. That northern wasteland; that land of blood, desolation and death is your dominion. Tonight we are going home."
~His Lordship
War Alert: OFF Raid Alert: OFF
PM a WG Official
 Math geek ahoy, A^2+b^2=C^2
Posted: March 6, 2009 03:41 pmTop
   


IRC Nickname: Olivier1o1
Group: Guest
Posts: 208
Member No.: 1744
Joined: February 27, 2009
Total Events Attended: 17
I'ma math geek, plain and simple, and I supplement my income teaching.

I'm willing to anwser any questions you have about math, I can do up to 1-2 years of college level math, and you can post literally any math (or physics) question here, because if I'm stumped, I'll look it up happy.gif has yet to fail for me.
 
--------------------

Posted: March 6, 2009 08:31 pmTop
   


IRC Nickname: davza108
Group: Ex-Member
Posts: 128
Member No.: 525
Joined: April 25, 2008
Total Events Attended: 0
Explain to me domain and range.
 
--------------------
Avidgamers vet.

Posted: March 6, 2009 10:21 pmTop
   
User Avatar

IRC Nickname: Maths
Group: Ex-Member
Posts: 1855
Member No.: 54
Joined: December 31, 2007
Total Events Attended: 286
Hai I maffs woeh.gif
 
--------------------
user posted image

"Journeys are what brings us happiness,
Not the destination."

~ Two time ex-raid leader of wg ~

user posted image

Posted: March 7, 2009 12:38 amTop
   


IRC Nickname: Mangomaniac2
Group: Emeritus
Posts: 536
Member No.: 70
Joined: December 31, 2007
Total Events Attended: 63
QUOTE (Davza108 @ March 06, 2009 08:31 pm)
Explain to me domain and range.

Do you seriously want help?

Domain is all the possible x-values, and range is all the possible y-values.

There we go hash.png
 
--------------------
user posted image

Posted: March 7, 2009 12:55 amTop
   
User Avatar

IRC Nickname: Wayne|Eregion2
Group: Emeritus
Posts: 3087
Member No.: 156
Joined: January 25, 2008
Total Events Attended: 8
A little off topic, but how do you like teaching? I'm thinking of maybe doing some tutoring on campus as a part-time job and was curious. smile.gif And if your offer includes calc1 I might have a few questions sometime.
 
--------------------
user posted image

Posted: March 7, 2009 12:58 amTop
   
User Avatar

IRC Nickname: Ty
Group: Ex-Member
Posts: 369
Member No.: 93
Joined: January 3, 2008
Total Events Attended: 34
What is the integral of x^x?
 
--------------------

user posted image

user posted image

user posted image

Posted: March 7, 2009 09:07 amTop
   
User Avatar

IRC Nickname: Dnovelta
Group: Emeritus
Posts: 2750
Member No.: 130
Joined: January 20, 2008
Total Events Attended: 137
QUOTE (Mr Death 13 @ March 07, 2009 01:58 am)
What is the integral of x^x?

Unless I'm just thinking in terms of basic integration, the integral of x^x should be something like this:

1/x+1(x^x+1)

Because when you derive it, you'd use the power rule and bring the x+1 over and make it the co-efficient, so it'd multiply by the 1/x+1, but would also cancel out = 1, meaning no visible co-efficient. At the same time, because you're deriving and using the power rule, you'd subtract 1 from the original power (x+1) which would result in just x.

Your end result would be x^x.
 
--------------------
user posted image
user posted image

Posted: March 7, 2009 10:18 amTop
   
User Avatar

IRC Nickname: Matt|Georgio9
Group: Emeritus
Posts: 706
Member No.: 94
Joined: January 3, 2008
Total Events Attended: 0
QUOTE (Mangomaniac2 @ March 07, 2009 12:38 am)
QUOTE (Davza108 @ March 06, 2009 08:31 pm)
Explain to me domain and range.

Do you seriously want help?

Domain is all the possible x-values, and range is all the possible y-values.

There we go hash.png

Not necessarily. If you're in the complex domain, the domain of a function will be some magnitude and some angle range that make up the output of a function, the range.

|x +iy| = 1, angle pi/4

|x - iy| = 1, angle 7pi/4
 
--------------------
user posted imageuser posted image

Posted: March 7, 2009 10:02 pmTop
   


IRC Nickname:
Group: Clan Friend
Posts: 31
Member No.: 1716
Joined: February 13, 2009
Total Events Attended: 0
QUOTE (1colonel1 @ March 07, 2009 04:07 am)
QUOTE (Mr Death 13 @ March 07, 2009 01:58 am)
What is the integral of x^x?

Unless I'm just thinking in terms of basic integration, the integral of x^x should be something like this:

1/x+1(x^x+1)

Because when you derive it, you'd use the power rule and bring the x+1 over and make it the co-efficient, so it'd multiply by the 1/x+1, but would also cancel out = 1, meaning no visible co-efficient. At the same time, because you're deriving and using the power rule, you'd subtract 1 from the original power (x+1) which would result in just x.

Your end result would be x^x.

um...no. integral(x^x) isn't easily expressed as a function.
If you are curious as to why
http://mathworld.wolfram.com/Integral.html

I'm not going to go through thoroughly why the above explanation is wrong, just notice that you can't "anti" chain rule like that, because our 1/x would also have its own derivative, namely -1/x^2

if you need a definite integration of x^x over some integral, some values can be achieved
 
--------------------

Posted: March 7, 2009 11:10 pmTop
   
User Avatar

IRC Nickname: Mtoise
Group: Ex-Member
Posts: 715
Member No.: 1691
Joined: February 5, 2009
Total Events Attended: 60
You are all wrong

The integral of X^X is HAHAHAHWTFIRLBBQ RUNESCAPE!
 
--------------------
"Do not believe everything that is written on the internet; for it may just be a bag of lies" - George Washington 1873 -




On the long winding road to 99 slayer. 98 to 99 Slay without killing a thing.

22/28 effigy's PM me if you can assist Construction Effigy's

Posted: March 8, 2009 02:18 amTop
   
User Avatar

IRC Nickname: Sithofwookie
Group: Ex-Member
Posts: 2842
Member No.: 815
Joined: June 11, 2008
Total Events Attended: 48
QUOTE (mtoise @ March 07, 2009 03:10 pm)
You are all wrong

The integral of X^X is HAHAHAHWTFIRLBBQ RUNESCAPE!

I thought Runescape was the answer to all problems.
 
--------------------
user posted image

Posted: March 8, 2009 06:17 amTop
   
User Avatar

IRC Nickname: Dnovelta
Group: Emeritus
Posts: 2750
Member No.: 130
Joined: January 20, 2008
Total Events Attended: 137
Yeah, wasn't sure about my thinking. Just starting basic calculus, so was giving it a shot, haha.

EDIT:

Wait, I wasn't doing any chain-rule, I don't think.

I used the parenthesis not to signify multiplication, but to just show it's a different value.

My reasoning is probably still flawed, but I was just using the idea of:

Integral of X^2 = 1/3*X^3. You bring the 3 from the X^3 over because of the power rule, which would cause it to cancel out with the 1/3. You would then subtract 1 from the 3, making it 2. Your end result would be X^2.

What I did was simply replace the 3 with X+1.

I'm probably still missing something, but yeah.
 
--------------------
user posted image
user posted image

Posted: March 8, 2009 07:14 amTop
   
User Avatar

IRC Nickname: Ty
Group: Ex-Member
Posts: 369
Member No.: 93
Joined: January 3, 2008
Total Events Attended: 34
yeah I was just messing with you it can't be integrated tongue.gif
 
--------------------

user posted image

user posted image

user posted image

Posted: March 8, 2009 04:37 pmTop
   
User Avatar

IRC Nickname: Wayne|Eregion2
Group: Emeritus
Posts: 3087
Member No.: 156
Joined: January 25, 2008
Total Events Attended: 8
Could you integrate it using logarithms somehow? (Haven't gotten to integrals yet).
 
--------------------
user posted image

Posted: March 8, 2009 08:09 pmTop
   
User Avatar

IRC Nickname: Matt|Georgio9
Group: Emeritus
Posts: 706
Member No.: 94
Joined: January 3, 2008
Total Events Attended: 0
Well this is horrible.

I tried to integrate x^x with my crazy math software Maple 11, and it failed. It just left it in the original form. It couldn't come up with a general integral to model it with.

I'll give MATLAB a try in a bit.
 
--------------------
user posted imageuser posted image

Posted: March 8, 2009 09:11 pmTop
   
User Avatar

IRC Nickname: Wayne|Eregion2
Group: Emeritus
Posts: 3087
Member No.: 156
Joined: January 25, 2008
Total Events Attended: 8
Speaking of which, how the heck would you take the derivative of a logarithm. Serious question.

// edit //

Nvm, I guess you'd just take the derivative before putting it in logarithmic form.
 
--------------------
user posted image

Posted: March 9, 2009 04:29 amTop
   


IRC Nickname:
Group: Clan Friend
Posts: 31
Member No.: 1716
Joined: February 13, 2009
Total Events Attended: 0
QUOTE (Eregion2 @ March 08, 2009 04:11 pm)
Speaking of which, how the heck would you take the derivative of a logarithm. Serious question.

// edit //

Nvm, I guess you'd just take the derivative before putting it in logarithmic form.

alternatively, d(ln f(x))/dx = f'(x)/f(x)

where f is a function of x
 
--------------------

Posted: March 9, 2009 07:23 pmTop
   


IRC Nickname: Olivier1o1
Group: Guest
Posts: 208
Member No.: 1744
Joined: February 27, 2009
Total Events Attended: 17
QUOTE (Eregion2 @ March 06, 2009 07:55 pm)
A little off topic, but how do you like teaching? I'm thinking of maybe doing some tutoring on campus as a part-time job and was curious. smile.gif And if your offer includes calc1 I might have a few questions sometime.

Ok, I can do calc 1, calc 2, and a few more levels in, I self-taught myself some of it.

Sorry, I didn't check this for a day or two, was really busy.

In reverse, d lnx / dx = 1/x

What you do is raise both sides to e^x

then the form of a^u = a^u lna Du/Dx


x^x is a nightmare. I did it once.


GTG catch my bus, finish up later
 
--------------------

Posted: March 10, 2009 01:35 amTop
   
User Avatar

IRC Nickname: Plano|Adam
Group: Emeritus
Posts: 1449
Member No.: 228
Joined: February 13, 2008
Total Events Attended: 107
QUOTE (Georgio9 @ March 07, 2009 05:18 am)
QUOTE (Mangomaniac2 @ March 07, 2009 12:38 am)
QUOTE (Davza108 @ March 06, 2009 08:31 pm)
Explain to me domain and range.

Do you seriously want help?

Domain is all the possible x-values, and range is all the possible y-values.

There we go hash.png

Not necessarily. If you're in the complex domain, the domain of a function will be some magnitude and some angle range that make up the output of a function, the range.

|x +iy| = 1, angle pi/4

|x - iy| = 1, angle 7pi/4

i think i just pooped in my pants, and i realllly do not wanna take math in college.

fack.
 
--------------------
user posted image
"If at first you don’t succeed, call it version 1.0"

Posted: March 10, 2009 06:11 amTop
   
User Avatar

IRC Nickname: Matt|Georgio9
Group: Emeritus
Posts: 706
Member No.: 94
Joined: January 3, 2008
Total Events Attended: 0
QUOTE (Planolocal @ March 10, 2009 01:35 am)
QUOTE (Georgio9 @ March 07, 2009 05:18 am)
QUOTE (Mangomaniac2 @ March 07, 2009 12:38 am)
QUOTE (Davza108 @ March 06, 2009 08:31 pm)
Explain to me domain and range.

Do you seriously want help?

Domain is all the possible x-values, and range is all the possible y-values.

There we go hash.png

Not necessarily. If you're in the complex domain, the domain of a function will be some magnitude and some angle range that make up the output of a function, the range.

|x +iy| = 1, angle pi/4

|x - iy| = 1, angle 7pi/4

i think i just pooped in my pants, and i realllly do not wanna take math in college.

fack.

Unless you're going into electrical engineering (like me) or some kind of crazy pure physics or you're just looking to pick up a math course, you won't need to take a complex analysis course like what I'm taking.

Sure it'll be good to know how to deal with imaginary numbers....well even real numbers in cylindrical coordinates or polar coordinates but you probably won't use them. besides, there are calculators that can do all this stuff for you.

PS - No one actually likes math, it's just something that comes along with other courses. That only people who like math are majoring in it or are just straight up unbalanced.
 
--------------------
user posted imageuser posted image

Posted: March 10, 2009 01:18 pmTop
   


IRC Nickname: Olivier1o1
Group: Guest
Posts: 208
Member No.: 1744
Joined: February 27, 2009
Total Events Attended: 17
QUOTE (Mr Death 13 @ March 08, 2009 02:14 am)
yeah I was just messing with you it can't be integrated tongue.gif

Actually Mr. Death, you're wrong. It is possible to integrate ANYTHING. It can just be a pain to do, and you may end up with an infinite (taylor) series. But everything is integratable.



x^x is (lnx+1)*x^x*x+(x^(X-1))*(x*lnx^2+2xlnx+x+1)*x^2/2........ as I said, it's a pain.... that series goes on, and on, generalized by this: F^N(x)*x^n/n!, where f^n(x) is the nth derivative., and n is the number in the sequence.
 
--------------------

Posted: March 12, 2009 10:49 pmTop
   


IRC Nickname:
Group: Clan Friend
Posts: 31
Member No.: 1716
Joined: February 13, 2009
Total Events Attended: 0
QUOTE (Olivier1o1 @ March 10, 2009 08:18 am)
QUOTE (Mr Death 13 @ March 08, 2009 02:14 am)
yeah I was just messing with you it can't be integrated tongue.gif

Actually Mr. Death, you're wrong. It is possible to integrate ANYTHING. It can just be a pain to do, and you may end up with an infinite (taylor) series. But everything is integratable.



x^x is (lnx+1)*x^x*x+(x^(X-1))*(x*lnx^2+2xlnx+x+1)*x^2/2........ as I said, it's a pain.... that series goes on, and on, generalized by this: F^N(x)*x^n/n!, where f^n(x) is the nth derivative., and n is the number in the sequence.

lol he speaks the truth, anything that can be graphed can be integrated, that is to say it has area underneath its curve.

depending on the limits, it could be infinite

depending on the curve, it could be really hard to find, and it even if you can find it, you may end up with something that just makes you go "wtf am i supposed to do with you?"
 
--------------------

Posted: March 13, 2009 02:17 pmTop
   


IRC Nickname: Olivier1o1
Group: Guest
Posts: 208
Member No.: 1744
Joined: February 27, 2009
Total Events Attended: 17
it is infinite, that's the point of a taylor series. The only question is, how accurate do you want your approximation? Within the first few terms, you get more and more accurate, and the further from 0, the less accurate.... kinda complicated, but meh. it works.

=D Olivier:1 unbelievers:0
 
--------------------