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 Dividing by Zero
 
WG_Keanu
Posted: September 22, 2009 03:36 pmTop
   
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 Continuing my argument from http://www.wildernessguardians.com/forum/i...showtopic=11563

10 / (-1) = -10
Yes?

and 10 / 1 = 10

So put everything halfway there...

10 / (halfway between 1 and -1) = (halfway between 10 and -10)

10 / 0 = 0

Discuss.
 
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[05:42] <+WG_Keanu> I think I got a semi just looking at the pic
[05:42] <%kat> same
ThisIsUnique
Posted: September 22, 2009 03:52 pmTop
   
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 deviding by zero is not possible
can u divide a cake into 7parts?
yes
can u divide a cake into 0parts? no u cant
 
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Eregion2
Posted: September 22, 2009 04:55 pmTop
   
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 Zero isn't a number, it's a concept. You can't divide by it either way.
 
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Renegade3540
Posted: September 22, 2009 05:01 pmTop
   


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QUOTE (Ludo Slayer @ September 22, 2009 10:52 am)

deviding by zero is not possible
can u divide a cake into 7parts?
yes
can u divide a cake into 0parts? no u cant

But what if the cake is a lie?
 
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Eregion2
Posted: September 22, 2009 05:03 pmTop
   
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QUOTE (Renegade3540 @ September 22, 2009 12:01 pm)

QUOTE (Ludo Slayer @ September 22, 2009 10:52 am)

deviding by zero is not possible
can u divide a cake into 7parts?
yes
can u divide a cake into 0parts? no u cant

But what if the cake is a lie?

0 / 7 = 0.
 
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Fullmetal792
Posted: September 22, 2009 05:04 pmTop
   
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QUOTE (Renegade3540 @ September 22, 2009 12:01 pm)

QUOTE (Ludo Slayer @ September 22, 2009 10:52 am)

deviding by zero is not possible
can u divide a cake into 7parts?
yes
can u divide a cake into 0parts? no u cant

But what if the cake is a lie?

Then you obviously live in a closed enviornment, can make portals with a gun, and have a computer trying to kill you. I don't think you'd care much about dividing by zero, unless you want to overload the computer with errors.
 
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chip54321
Posted: September 22, 2009 07:48 pmTop
   
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 Try substituting a number incredibly close to zero (ex: 1/inf.)

1/(1/inf.)
the rule for dividing fractions is to flip it then multiply, so you get 1*inf. Since infinity doesn't exist, neither does 1 divided by zero.
 
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Sonixpber
Posted: September 22, 2009 08:19 pmTop
   
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 /me divides by zero..

/me explodes.
 
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Eregion2
Posted: September 22, 2009 08:53 pmTop
   
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QUOTE (Sonixpber @ September 22, 2009 03:19 pm)

/me divides by zero..

/me explodes.

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WG_Keanu
Posted: September 22, 2009 10:42 pmTop
   
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QUOTE (Eregion2 @ September 22, 2009 05:55 pm)

Zero isn't a number, it's a concept. You can't divide by it either way.

Ah, so how do you work with a concept? You add in another concept biggrin.gif At least someone agrees.

@ Ludo

Divide a cake by 0 pieces? Eat the cake lol

cake = x

if x / 0 = 0

Then to divide a cake into 0 pieces the cake itself must not exist, hence the answer is 0.

Just admit I'm right.
 
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[05:42] <+WG_Keanu> I think I got a semi just looking at the pic
[05:42] <%kat> same
Samurai-JM
Posted: September 22, 2009 11:03 pmTop
   
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 math doesn't work like that, what is that doing there? what is this i don't even
 
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Kiwi011
Posted: September 23, 2009 07:18 amTop
   
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 this leads to the thought process of Are negative numbers real, since you can't have a negative anything irl.

-3 apples does not exist.
 
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Bassism
Posted: September 23, 2009 07:37 amTop
   
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QUOTE (WG_Keanu @ September 22, 2009 10:42 pm)

Just admit I'm right.

Yes, I'm pretty sure you just solved a problem mathematicians the world over have struggled with constantly. You, Keanu, are a genius. dry.gif
 
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WG_Keanu
Posted: September 23, 2009 03:08 pmTop
   
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QUOTE (Bassism @ September 23, 2009 08:37 am)

QUOTE (WG_Keanu @ September 22, 2009 10:42 pm)

Just admit I'm right.

Yes, I'm pretty sure you just solved a problem mathematicians the world over have struggled with constantly. You, Keanu, are a genius. dry.gif

I'm glad you support biggrin.gif

Kiwi, the great thing about maths is you can work with theory that's physically impossible tongue.gif
 
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[05:42] <+WG_Keanu> I think I got a semi just looking at the pic
[05:42] <%kat> same
Kiwi011
Posted: September 23, 2009 07:52 pmTop
   
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Nick
Posted: September 23, 2009 09:05 pmTop
   
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 So what is the (√-3)?
 
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Sonixpber
Posted: September 23, 2009 11:07 pmTop
   
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QUOTE (Lefty2802 @ September 23, 2009 09:05 pm)

So what is the (√-3)?

A mathematical genius such as Keanu should be able to answer this. Without using irrational numbers, of course.
 
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30 Str 0wnz
Posted: September 24, 2009 12:18 amTop
   
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 EDIT: Meh fuck it, I'm not doing math for the rest of the year.

 
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WG_Keanu
Posted: September 24, 2009 03:49 amTop
   
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QUOTE (Lefty2802 @ September 23, 2009 10:05 pm)

So what is the (√-3)?

√x = y when yy = x

√(-3) = y when yy = (-3)

to begin, (-3) = yy

[DIVIDE BY Y] and (-3)/y = y

[DIVIDE BY Y] then ((-3)/y)/y = 0

hence 0*y = (-3)/y

and 0*a = 0, with a being any value

so if (-3)/y = 0

[DIVIDE BY Y] then (-3) = 0*y

and if 0*y = 0

Then (-3) = 0

To answer your question Lefty, if (-3) = 0, then √0 = 0.

I eat your paradoxes for breakfast.
 
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[05:42] <+WG_Keanu> I think I got a semi just looking at the pic
[05:42] <%kat> same
Mangomaniac2
Posted: September 24, 2009 07:43 pmTop
   


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QUOTE (WG_Keanu @ September 24, 2009 03:49 am)

[DIVIDE BY Y] and (-3)/y = y

[DIVIDE BY Y] then ((-3)/y)/y = 0

hence 0*y  = (-3)/y

On the second line that I quoted, you divide both sides by Y a second time. So the left is fine, but on the right side of the equation, Y/Y = 1, not 0 tface.gif


P.S. Have you heard of "eye"?
 
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Mangomaniac2
Posted: September 24, 2009 07:45 pmTop
   


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QUOTE (Bassism @ September 23, 2009 07:37 am)

QUOTE (WG_Keanu @ September 22, 2009 10:42 pm)

Just admit I'm right.

Yes, I'm pretty sure you just solved a problem mathematicians the world over have struggled with constantly. You, Keanu, are a genius. dry.gif

Owen wub.gif
 
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Mangomaniac2
Posted: September 24, 2009 07:47 pmTop
   


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QUOTE (WG_Keanu @ September 22, 2009 10:42 pm)

Divide a cake by 0 pieces? Eat the cake lol

cake = x

if x / 0 = 0

Then to divide a cake into 0 pieces the cake itself must not exist, hence the answer is 0.

Amazing reasoning ability here

EDIT: triple post happy.gif
 
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Nick
Posted: September 24, 2009 08:40 pmTop
   
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QUOTE (WG_Keanu @ September 23, 2009 10:49 pm)

               
QUOTE (Lefty2802 @ September 23, 2009 10:05 pm)

So what is the (√-3)?

√x = y when yy = x

√(-3) = y when yy = (-3)

to begin, (-3) = yy

[DIVIDE BY Y] and (-3)/y = y

[DIVIDE BY Y] then ((-3)/y)/y = 0

hence 0*y = (-3)/y

and 0*a = 0, with a being any value

so if (-3)/y = 0

[DIVIDE BY Y] then (-3) = 0*y

and if 0*y = 0

Then (-3) = 0

To answer your question Lefty, if (-3) = 0, then √0 = 0.

I eat your paradoxes for breakfast.

Actually in your 6th line, you are just making shit up.

If you multiply each side by y, then you would end back up with y=(-3)/y. Same thing happens in line 9.

EDIT: Also, (-3) is not equal to 0 thus making your whole reasoning obsolete.
 
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Fullmetal792
Posted: September 24, 2009 08:55 pmTop
   
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QUOTE (Mangomaniac2 @ September 24, 2009 02:43 pm)

               
QUOTE (WG_Keanu @ September 24, 2009 03:49 am)

[DIVIDE BY Y] and (-3)/y = y

[DIVIDE BY Y] then ((-3)/y)/y = 0

hence 0*y  = (-3)/y

On the second line that I quoted, you divide both sides by Y a second time. So the left is fine, but on the right side of the equation, Y/Y = 1, not 0 tface.gif

This, thus making it:

(-3)/(y^2)=1

Meaning your equation is wrong, meaning that your credibility is shot. Also, Lefty hit the end of the problem dead on. -3 doesn't = 0, but you were also wrong from line 5, so your answer was going to be wrong.
 
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Thanks Sam for an awesome job and an awesome wait!
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sgtswordfish
Posted: September 24, 2009 09:18 pmTop
   
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 i think these guys covered it well. btw, 0 dosen't exist.

one drill my teacher used to do is ask us which number real numbers started. everyone would say 0. that's how i learned imaginary numbers. 0 is the start of the pack.
 
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